CBSE Class 10 Answered
sir
Asked by manoj255 | 03 Jan, 2010, 06:50: PM
Expert Answer
consider 2sec2a-sec4a-2cosec2a+cosec4a=2(sec2a - cosec2a)+ (cosec4a-sec4a)
=(sec2a - cosec2a)(2-sec2a -cosec2a)
=(1+tan2a-1-cot2a)(1-sec2a+1-cosec2a)
-(tan2a-cot2a)(tan2a+cot2a) = -tan4a+cot4a =RHS
Answered by | 04 Jan, 2010, 10:34: AM
Application Videos
Concept Videos
CBSE 10 - Maths
Asked by swetalinasamantaray022 | 21 Mar, 2023, 04:15: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shanbhog.06 | 14 Apr, 2022, 11:26: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by badakhsharda | 14 Apr, 2022, 08:57: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by naancysingh | 09 Apr, 2022, 07:07: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by vy499292 | 23 Jan, 2022, 08:04: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by godboletanaya | 24 Dec, 2021, 11:08: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by nikunjgupta102021 | 12 Jul, 2021, 09:01: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by urzashu7818 | 15 Jan, 2021, 12:52: PM
ANSWERED BY EXPERT