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CBSE Class 10 Answered

sir
Asked by manoj255 | 03 Jan, 2010, 06:50: PM
answered-by-expert Expert Answer

consider 2sec2a-sec4a-2cosec2a+cosec4a=2(sec2a - cosec2a)+ (cosec4a-sec4a)

=(sec2a - cosec2a)(2-sec2a -cosec2a)

=(1+tan2a-1-cot2a)(1-sec2a+1-cosec2a)

-(tan2a-cot2a)(tan2a+cot2a) = -tan4a+cot4a =RHS

Answered by | 04 Jan, 2010, 10:34: AM
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