Sir plz solve it step by step ,U may leave part (b) but plz solve explaining part(a)

Asked by vishakhachandan026 | 8th Aug, 2019, 10:21: AM

Expert Answer:

Given:
 
For NO,
 
Volume = 0.25 L
 
Pressure = 800 torr
 
            equals space 800 over 760

equals 1.05 space atm
 
 
temperature = 220 K
 
By using gas equation, no. of moles can be calculated as,
 
PV = nRT
 
 
straight n equals PV over RT

space equals fraction numerator 1.05 cross times 0.25 over denominator 0.0821 cross times 220 end fraction

space straight n equals 0.0145 space mol
 
 
For O2 
For NO,
 
Volume = 0.1 L
 
Pressure = 600 torr
 
            equals space 600 over 760

equals 0.79 space atm
 
 
temperature = 220 K
By using gas equation, no. of moles can be calculated as,
 
PV= nRT
 
straight n equals PV over RT

space space equals fraction numerator 0.79 cross times 0.1 over denominator 0.0821 cross times 220 end fraction

straight n equals space 0.00437 space mol
 
The reaction to form N2O4 
 
2NO + O2 → N2O4 
 
2 mole of NO reacts with 1 mole of  O2 
 
so, 0.00437 mole of  O2 will require 
 
fraction numerator space 0.00437 cross times 2 over denominator 1 end fraction

equals 0.00874 space mol space of space NO
 
(a)
 
Excess of NO is : 0.0.145 - 0.00874 = 0.00578 mole of NO
 
Now aain by using gas law we can calculate pressure,
 
PV = nRT
 
straight P equals nRT over straight V

space space space space equals fraction numerator 0.00576 cross times 0.00821 cross times 220 over denominator open parentheses 0.25 plus 0.1 close parentheses end fraction

straight P equals 0.299 space atm
 
(b) From equation,
 
2 mole of NO gives 1 mole of N2O4 
 
so 0.00874 mole of NO will give,
 
equals fraction numerator 0.00874 cross times 1 over denominator 2 end fraction

equals 0.00437 space mole space of space straight N subscript 2 straight O subscript 4
 
Molar mass of N2O4 = 92g/mol
 
Mass of N2O4 = 92×0.00437
 
                    = 0.402 gm.
 
 

Answered by Varsha | 8th Aug, 2019, 12:52: PM

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