Sir plz solve it step by step,plzz

Asked by vishakhachandan026 | 30th Jul, 2019, 06:28: PM

Expert Answer:

Given:
For hydrogen,
 
Volume  = 0.5 m3 
 
Temperature = 20.5 °C
 
                   =273 + 20.5 = 293.5 K
 
Pressure = 611 × 103 Pa
 
Calculate no.of moles by using gas law,
 
PV space equals nRT

space space straight n space equals PV over RT

space space space space space space equals fraction numerator 611 cross times 10 cubed cross times 0.5 over denominator 293.5 cross times 8.314 end fraction

space space straight n space space equals 125 space mol
For argon,
 
Volume = 0.750 m3
 
Temperature =31.2 °C
 
                   = 273 + 31.2=304.2 K
 
Pressure = 433 × 103 Pa
 
Calculate no.of moles by using gas law,
 
PV =nRT
 
straight n equals PV over RT

space space space equals fraction numerator 433 cross times 10 cubed cross times 0.75 over denominator 8.314 cross times 304.2 end fraction

straight n space equals 128 space mol
 
Total no. of moles = 125+128 = 253 mole
 
Final temperature = 14.5 °C
 
Final volume = 0.5 +0.75 = 1.25 m3
 
                          = 273 + 14.5 =287.5 K K
PV = nRT
 
straight P equals nRT over straight V

space space space equals fraction numerator 253 cross times 8.314 cross times 287.5 over denominator 1.25 end fraction

straight P space equals space 4.837 cross times 10 to the power of 5 space end exponent Pa
 
The final pressure of the vessle is 4.837 × 105 Pa
 
 
 
 
 
 
 

Answered by Varsha | 2nd Aug, 2019, 12:30: PM

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