Sir plz solve it step by step

Asked by vishakhachandan026 | 26th Jul, 2019, 03:05: PM

Expert Answer:

Given:
 
Volume of mixture of gases = 28 L
 
Pressure = 1atm
 
Temperature = 273 K
 
Using gas equation,
 
PV = nRT
 
straight n equals PV over RT

space equals fraction numerator 1 cross times 28 over denominator 0.082 cross times 273 end fraction

space equals 1.25 space mol
 
 
 
let C2H4 = x
 
C2H6 = y
 
x + y = 1.25 mol  ....(1)
 
The mixture of gases reacts with O2 
 
straight C subscript 2 straight H subscript 4 space plus space 3 straight O subscript 2 space rightwards arrow space 2 CO subscript 2 space plus space 2 straight H subscript 2 straight O

straight C subscript 2 straight H subscript 6 space plus space bevelled 7 over 2 straight O subscript 2 space rightwards arrow space 2 CO subscript 2 space plus space 3 straight H subscript 2 straight O
Mixture completely reacts with 128 gm of O2 
 
 equals 128 over 32

equals space 4 space mole
 
Now,
 
3 straight x space plus fraction numerator 7 straight y over denominator 2 end fraction equals space 4 space space.... open parentheses 2 close parentheses
 
From eq (1) and (2) 
 
y= 0.5 mol
 
Mole fraction of C2H4
 
equals fraction numerator 0.5 over denominator 1.25 end fraction

equals space 0.4 space
 
So mole fraction of C2H4 = 1- 0.4 
 
                                    = 0.6
 
 

Answered by Varsha | 26th Jul, 2019, 05:34: PM

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