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Sir pls solve the following.
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Asked by rsudipto | 27 Dec, 2018, 21:51: PM
answered-by-expert Expert Answer
(2-x-x2)2n = a0 + a1x + a2x2 + a3x3 + ...........................(1)
 
Let us substitute x =1 in eqn.(1), then we have, 
 
a0 + a1 + a2 + a3 + a4 ................. =  0
 
Hence,  a0 + a2 +  a4 ................ = - ( a1 + a3 + a5 + ................ )         ........................(2)
 
Let us substitute x = -1 in eqn.(1), then we have,
 
22n = a0 - a1 + a2 - a3 + a4 - a5 +......................
 
Hence,  22n =( a0 + a2 + a4+ .............) - (a1  + a3  + a5 +...................... )   ...................(3)
 
using equation (2), equation (3) can be written as ,   22n = 2 ( a0 + a2 + a4+ .............)
 
hence   ( a0 + a2 + a4+ .............) = 22n-1
 
 
 
Answered by Thiyagarajan K | 27 Dec, 2018, 23:50: PM

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