JEE Class main Answered
Sir pls solve the following.
Asked by rsudipto | 02 Jan, 2019, 07:40: PM
Expert Answer
Force is given by F=iLBsinΘ
Putting the values F= 5×0.25.×0.25×sin65 =0.3125sin65.
Answered by Ankit K | 03 Jan, 2019, 10:58: AM
JEE main - Physics
Asked by aaryamanmodern | 14 Aug, 2023, 10:20: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by mc8may | 18 Jul, 2023, 10:21: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by aaryamanmodern | 15 Jul, 2023, 01:02: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by yashsanvordekar | 24 Jun, 2022, 10:42: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by manvirsingh2242 | 21 Jun, 2022, 10:20: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by arjunsah797 | 25 Jan, 2022, 09:31: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by arjunsah797 | 24 Jan, 2022, 04:14: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by Vipulgautam050 | 27 Oct, 2021, 11:47: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by shamkishor8 | 01 Oct, 2021, 09:05: PM
ANSWERED BY EXPERT