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JEE Class main Answered

Sir pls solve the following.
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Asked by rsudipto | 02 Jan, 2019, 07:40: PM
answered-by-expert Expert Answer
Force is given by F=iLBsinΘ
Putting the values F= 5×0.25.×0.25×sin65 =0.3125sin65.
Answered by Ankit K | 03 Jan, 2019, 10:58: AM
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