Sir, pls solve the following.

Asked by rsudipto | 25th Dec, 2018, 09:59: AM

Expert Answer:

 
 
Given colon space
moles space of space straight A space equals 2 space moles
moles space of space straight B space equals 3 space moles space
moles space of space straight C space equals space 2 space moles
Volume space equals space 2 space straight L
left square bracket straight C right square bracket space equals 0.5 space mol divided by straight l

Find colon space Kc space equals ?

Solution colon
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space straight A space space space space space plus space space 2 straight B space space space rightwards harpoon over leftwards harpoon space space space space 2 straight C
Let space straight t space equals 0 space space space space space space space space space space space space space space space space space space 2 space space space space space space space space space space space space 3 space space space space space space space space space space space space space 2

space space space space space space space space space space space straight t equals straight t space space space space space space space space space open parentheses 2 minus straight x close parentheses space space open parentheses 3 minus 2 straight x close parentheses space space space space space open parentheses 2 straight x plus 2 close parentheses space

As space given comma
space left square bracket straight C right square bracket space equals space 0.5 space mol divided by lit

space space space space space space space space equals space fraction numerator left parenthesis 2 straight x space plus space 2 right parenthesis over denominator 2 end fraction
space space space space straight x space equals space minus 0.5
Put space straight x equals space minus 0.5 space at space time space straight t comma
Thus space straight A space equals space left parenthesis 2 minus straight x right parenthesis space equals space left curly bracket 2 minus left parenthesis negative 0.5 right parenthesis right curly bracket space equals space 2.5
space space space space space space space space space space space space space straight B space equals left parenthesis 3 minus 2 straight x right parenthesis space equals space left curly bracket 3 minus 2 left parenthesis negative 0.5 right parenthesis right curly bracket space equals space left parenthesis 3 plus 1 right parenthesis space equals space 4
space space space space space space space space space space space space space straight C space equals space left parenthesis 2 straight x plus 2 right parenthesis space equals space left curly bracket 2 left parenthesis negative 0.5 right parenthesis space plus space 2 right curly bracket space equals space left parenthesis negative 1 plus 2 right parenthesis space equals space 1

Kc space equals space fraction numerator left square bracket straight C right square bracket squared over denominator left square bracket straight A right square bracket space left square bracket straight B right square bracket squared end fraction space space equals space fraction numerator open parentheses begin display style bevelled 1 half end style close parentheses squared over denominator open parentheses begin display style bevelled fraction numerator 2.5 over denominator 2 end fraction end style close parentheses. open parentheses begin display style bevelled 4 over 2 end style close parentheses squared end fraction space equals space fraction numerator open parentheses begin display style bevelled 1 fourth end style close parentheses over denominator open parentheses begin display style bevelled fraction numerator 2.5 over denominator 2 end fraction end style close parentheses open parentheses 4 close parentheses end fraction equals space fraction numerator open parentheses begin display style 1 fourth end style close parentheses over denominator open parentheses 5 close parentheses end fraction equals space 1 over 20 space equals space 0.05
 
 
Hence option C is correct.

Answered by Ramandeep | 3rd Jan, 2019, 06:12: PM

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