CBSE Class 10 Answered
SIR PLEASE PROVE
Asked by gunjansingh | 06 Dec, 2009, 06:18: PM
Expert Answer
[cot 2A(secA - 1)]/(1+sinA)
Multiply and divide by (1-sinA)(secA + 1) and using x2 - y2 = (x+y)(x-y)
[cot 2A(sec2A - 1)(1-sinA)]/[(1-sin2A)(secA + 1)] =
[cot 2A tan2A(1-sinA)]/[cos2A(secA + 1)] =
[(1-sinA)]/[cos2A(secA + 1)] =
[sec 2A(1-sinA)]/[1+secA]
Regards,
Team,
TopperLearning
Answered by | 06 Dec, 2009, 07:18: PM
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