SIR PLEASE PROVE
Asked by gunjansingh | 6th Dec, 2009, 06:10: PM
Expert Answer:
(cosecA - secA ) ( cotA - tanA) =
[(cosA - sinA)/(cosAsinA)][(cos2A - sin2A)/(cosAsinA)] =
[(cosA - sinA)(cosA - sinA)(cosA + sinA)]/(cosAsinA) =
[(cosA - sinA)2(cosA + sinA)]/(cosAsinA) =
[(cos2A + sin2A - 2sinAcosA)(cosA + sinA)]/(cosAsinA) =
[(1 - 2sinAcosA)(cosA + sinA)]/(cosAsinA) =
[(1 - 2sinAcosA)/(cosAsinA)][(cosA + sinA)/(cosAsinA)] =
(secA cosecA -2 )(cosecA + secA )
Regards,
Team,
TopperLearning.
Answered by | 6th Dec, 2009, 07:28: PM
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