tan to the power of 2 space end exponent A minus space tan squared B space equals space S i n squared A minus S i n squared B divided by C o s squared A. C o s squared B
Sir, PLease proove me the identity.

Asked by bigguyhareesrocks | 7th Mar, 2015, 10:41: AM

Expert Answer:

begin mathsize 12px style H e r e comma L. H. S. space equals space tan squared A space minus space tan squared B equals fraction numerator sin squared A over denominator cos squared A end fraction minus fraction numerator sin squared B over denominator cos squared B end fraction space equals fraction numerator s i n squared A cos squared B space minus space sin squared B cos squared A space over denominator c o s squared A cos squared B end fraction equals fraction numerator s i n squared A left parenthesis 1 space minus space sin squared B right parenthesis space minus space sin squared B left parenthesis 1 minus sin squared A right parenthesis space over denominator c o s squared A cos squared B end fraction equals fraction numerator s i n squared A space minus up diagonal strike space sin squared A. sin squared B end strike space minus space sin squared B plus up diagonal strike sin squared A. sin squared B end strike space over denominator c o s squared A cos squared B end fraction equals fraction numerator s i n squared A space minus sin squared B space over denominator c o s squared A. cos squared B end fraction equals space R. H. S. end style

Answered by Mili Hariyani | 7th Mar, 2015, 12:01: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.