Sir, Please give me a detailed description of why the d-orbitals split when the negative field due to ligands surrounds the metal atom/ion? How does it become assymetrical? Please give detailed explanation of the very same.
Asked by Ishita Puranik | 25th Dec, 2011, 12:51: PM
Under the experience of negative fied due to ligands or neutral molecules which have lone pair of electrons,the d-orbitals split into two levels i.e.t2g and eg.
When the complex is formed, the ligands destroy the degeneracy(same energy level) of these orbitals i.e.the orbitals have now different energies.In an isolated gaseous metal ion the five d-orbitals do all have same energy termed as degenerate.However,the energy of orbitals is raised because of repulsion between the field and the electrons on the metal.In most transition metal complexes either six or four ligands surround to metal giving octahedral or tetrahedral structures.
In these two cases the field produced by the ligand is not spherically symmetrcal.Thus,the d-orbitals are not all affected equally by ligand field and thus become asymmetrical.
Answered by | 25th Dec, 2011, 01:15: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number