SIR,PLEASE ANSWER MY QUESTION
               JOSEPH JOGS FROM ONE END A TO THE OTHER AND B OF A STRAIGHT 300M ROAD IN 2 MINUTES  50 SECONDS AND THEN AROUND AND JOGS 100M BACK TO POINT C IN ANOTHER I MINUTE. WHAT IS JOSEPH'S AVERAGE SPEED AND VELOCITY IN JOGGING
 
                            ( i) from Ato B
 
                            (ii) from A to C

Asked by cmkganesh | 22nd Jun, 2014, 07:54: PM

Expert Answer:

1. For motion from A to B:

distance travelled =300 m, time taken = 2 minutes and 50 sec =170 seconds.
displacement = 300 m
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Average velocity also equal to 1.76 m/s as displacement is same as distance.
2. For motion from A to C:

distance covered =300m + 100 m=400 m, time taken = 170 + 60 =230 sec
Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.
displacement = AB- BC =300 -100 =200 m
Therefore
Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.

Answered by Jyothi Nair | 23rd Jun, 2014, 08:50: AM