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CBSE Class 10 Answered

Sir, pl. answer my question
Asked by | 12 Mar, 2010, 09:47: AM
Expert Answer

3x=cosecθ  then x = cosecθ/3  and 1/x=cotθ/3

Consider 3(x2-1/x2) = 3( cosec2θ / 9 - cot2 θ/9)

=1/3(osec2θ  - cot2 θ)=1/3 (as cosec2θ - cot2 θ=1)

Answered by | 12 Mar, 2010, 11:07: AM
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