Sir, pl. answer my question

Asked by  | 12th Mar, 2010, 09:47: AM

Expert Answer:

3x=cosecθ  then x = cosecθ/3  and 1/x=cotθ/3

Consider 3(x2-1/x2) = 3( cosec2θ / 9 - cot2 θ/9)

=1/3(osec2θ  - cot2 θ)=1/3 (as cosec2θ - cot2 θ=1)

Answered by  | 12th Mar, 2010, 11:07: AM

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