Sir/Madam
Asked by bhanu24
| 29th Nov, 2009,
06:15: PM
Expert Answer:
Consider two stones of masses m1 and m2, m2
F1=Gm1M/r2
F2=Gm2M/r2
Now F1 = m1a1 and F2=m2a2
Now a1 = (Gm1M/r2)/m1 = GM/r2
a2 = (Gm2M/r2)/m2 = GM/r2
As we can see a1=a2, despite different masses.
Regards,
Team,
TopperLearning.
Answered by
| 29th Nov, 2009,
09:11: PM
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