Sir/Madam
Asked by bhanu24 | 29th Nov, 2009, 06:15: PM
Expert Answer:
Consider two stones of masses m1 and m2, m2
F1=Gm1M/r2
F2=Gm2M/r2
Now F1 = m1a1 and F2=m2a2
Now a1 = (Gm1M/r2)/m1 = GM/r2
a2 = (Gm2M/r2)/m2 = GM/r2
As we can see a1=a2, despite different masses.
Regards,
Team,
TopperLearning.
Answered by | 29th Nov, 2009, 09:11: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change