Asked by Nevin | 24th Sep, 2012, 12:57: PM

Expert Answer:

radius of drop =  r = 10^(-7) m
let the volume of the drop be: V = 4/3 (pi) r3 cu.m
thus mass of drop: m = pV
p = density of water
and g = gravitational acceleration
charge on drop: q = 1.6 x 10-19 C
thus force on drop: F = qE where E is the electric field
this should be enough to balance its mass:
F = mg

Answered by  | 24th Sep, 2012, 05:08: PM

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