SIR I POST U A QUESTION IN PREVIOUS DAYS;CALCULATE pH OF 1.0X10-8M SOLUTION OF HCL.PLEASE SIR READ CAREFULLY THAN GAVE ME ANS BECAUSE ANS. OF THIS QUESTION IS pH=6.98.
Asked by neetu athwal | 22nd Dec, 2013, 02:06: PM
Expert Answer:
HCl is a strong acid, it dissociates in aqueous solution.
Since pH = -log [H+], you need to find the concentration of H+ ([H+]).
Water dissociates as: H2O ? H+ + OH-
The dissociation constant is Kw = 10-7
So, 10-7 moles of H+ ions in pure water. By adding the 10-8 moles of HCl, the resulting concentration of H+ will be,
[H+] = 1.1 x 10-7
The negative log of 1.1 x 10-7 = 6.98, which is the pH value.
HCl is a strong acid, it dissociates in aqueous solution.
Since pH = -log [H+], you need to find the concentration of H+ ([H+]).
Water dissociates as: H2O ? H+ + OH-
The dissociation constant is Kw = 10-7
So, 10-7 moles of H+ ions in pure water. By adding the 10-8 moles of HCl, the resulting concentration of H+ will be,
[H+] = 1.1 x 10-7
The negative log of 1.1 x 10-7 = 6.98, which is the pH value.
Answered by Hanisha Vyas | 22nd Dec, 2013, 03:49: PM
Related Videos
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change