CBSE Class 11-science Answered
Sir, I didn't understand that toy and bowl example ( IN HOW MANY WAYS CAN 7 TOYS BE DISTRIBUTED IN 3 BOWLS/IN HOW MANY WAYS CAN 7 TOYS BE DISTRIBUTED IN 3 BOWLS SUCH THAT EACH BOWL HAS AT LEAST ONE TOY)in the video.
Asked by Koushtav Chakrabarty | 04 Oct, 2012, 01:23: PM
Expert Answer
1)
As we know there are three choices (3 bowls) for each of the 7 toys. Therefore, by the fundamental principle of multiplication ,the
total number of ways = 3 x 3 x 3 x 3 x 3 x 3 x 3 = 37= 2,187 ways.
2)
Any three toys can be arranged in 3 bowls in 3! = 6 ways,
Now remaining 4 toys where a bowl can hold any number of toys.
So number of ways of putting those 4 toys in 3 bowls is 34 = 81.
Total number of ways = 6x81 = 486
Answered by | 08 Nov, 2012, 11:04: AM
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