Sir, I didn't understand that toy and bowl example ( IN HOW MANY WAYS CAN 7 TOYS BE DISTRIBUTED IN 3 BOWLS/IN HOW MANY WAYS CAN 7 TOYS BE DISTRIBUTED IN 3 BOWLS SUCH THAT EACH BOWL HAS AT LEAST ONE TOY)in the video.

Asked by Koushtav Chakrabarty | 4th Oct, 2012, 01:23: PM

Expert Answer:

1) 

As we know there are three choices (3 bowls) for each of the 7 toys.  Therefore, by  the fundamental principle of multiplication ,the

total number of ways = 3 x 3 x 3 x 3 x 3 x 3 x 3 = 37= 2,187 ways.

2)

Any three toys can be arranged in 3 bowls in 3! = 6 ways,
Now remaining 4 toys where a bowl can hold any number of toys.
So number of ways of putting those 4 toys in 3 bowls is 34 = 81.
Total number of ways = 6x81 = 486

Answered by  | 8th Nov, 2012, 11:04: AM

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