sir fast exam

Asked by pranavjain | 19th Feb, 2010, 06:33: PM

Expert Answer:

If (y-2) is a factor, then y = 2 satisfies the equation,

my2+5y+n = 0

4m+10+n = 0

4m + n = 10            ....(1)

Also if (y-1/2) is a factor, then

m/4 +5/2 + n = 0

m + 10 + 4n  = 0 .....(2)

Subracting (1) from (2),

-3m + 3n = 0

m = n.

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Answered by  | 20th Feb, 2010, 05:30: AM

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