CBSE Class 12-science Answered
Sir can you answer the following question?
Asked by | 24 Sep, 2009, 02:10: PM
Expert Answer
Substitute y = tan x
dy/dx = sec2 x
dy = sec2 x dx
f(x) = (sec2 x sec2 x)/
tan x
= (1 + tan2 x)(sec2 x)/tan x
Hence f(x) dx = (1 + tan2 x)(sec2 x)dx/tan x
f(x) dx = (1 + y2)dy/y1/2 = f(y)dy
(y-1/2 + y2-1/2)dy = (y-1/2 + y3/2)dy
= 2y1/2 + 2y5/2/5
= 2tan x (5 + tan2 x)/5
Regards,
Team,
TopperLearning.
Answered by | 25 Sep, 2009, 03:34: PM
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