Since my exam is tomorrow , I hereby kindly request to answer this question ASAP . Thanks in advance !

Asked by Saravanan | 1st Oct, 2013, 04:08: PM

Expert Answer:

Let us assume that 9n ends with a digit 2, for some integer n.
So, it should have 2 in its prime factorisation.
But we know that the prime factorisation of 9 is 3 x 3.
So, 9n = (3 x 3)n
Hence, 9n contains only 3 as its prime factor.
So our assumption is wrong and hence 9n can't end with a digit 2.

Answered by  | 1st Oct, 2013, 04:51: PM

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