sin 47 + sin 61 - sin11 - sin 25
Asked by | 1st Sep, 2012, 11:17: AM
Expert Answer:
(sin47 - sin25) + (sin61 - sin11)
(2cos36 x sin11) + (2cos36 x sin25)
2cos36 ( sin11 + sin25)
4cos36 x sin18 x cos7
sin18 = (root5 - 1)/4 and cos36 = (root5 + 1)/4
so on solving we get, cos7.
(sin47 - sin25) + (sin61 - sin11)
(2cos36 x sin11) + (2cos36 x sin25)
2cos36 ( sin11 + sin25)
4cos36 x sin18 x cos7
sin18 = (root5 - 1)/4 and cos36 = (root5 + 1)/4
so on solving we get, cos7.
Answered by | 2nd Sep, 2012, 11:35: AM
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