CBSE Class 10 Answered
similar triangles
Asked by | 12 Mar, 2009, 09:46: AM
Expert Answer
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Given: AP:PB = 3:2
CQ:QD = 4:1
To prove: AR = 3/7 AC
Solution:
In 
APR and RQC
ARP = QRC (Vertically opposite angles)
APR = RQC (alternate angles)
PAR = RCQ (alternate angles)
APR 
RQC (AAA similarity criterian)
Answered by | 03 Apr, 2009, 11:24: AM
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