similar triangles

Asked by  | 12th Mar, 2009, 09:46: AM

Expert Answer:

  Given: AP:PB = 3:2 CQ:QD = 4:1 To prove: AR = 3/7 AC Solution: In APR and RQC ARP = QRC                 (Vertically opposite angles) APR = RQC                 (alternate angles) PAR = RCQ                 (alternate angles) APR  RQC              (AAA similarity criterian)

Aswered by  | 3rd Apr, 2009, 11:24: AM

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