similar triangles

Asked by  | 12th Mar, 2009, 09:46: AM

Expert Answer:

 

Given: AP:PB = 3:2

CQ:QD = 4:1

To prove: AR = 3/7 AC

Solution:

In APR and RQC

ARP = QRC                 (Vertically opposite angles)

APR = RQC                 (alternate angles)

PAR = RCQ                 (alternate angles)

APR  RQC              (AAA similarity criterian)

Answered by  | 3rd Apr, 2009, 11:24: AM

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