Silver crystallizes in fcc unit.Each side of the unit cell has a length of 409pm.What is the radius of silver atom ?

Asked by Pratik | 10th Oct, 2015, 12:07: PM

Expert Answer:

Let r be the radius and a is the edge length of the unit cell.
For FCC lattice,
straight r equals fraction numerator straight a over denominator 2 square root of 2 end fraction straight r equals fraction numerator 409 over denominator 2 cross times 1.414 end fraction straight r equals 144.6 space pm

Answered by Prachi Sawant | 10th Oct, 2015, 04:15: PM