CBSE Class 11-science Answered
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Asked by | 21 Sep, 2008, 08:01: AM
Expert Answer
we know that roots of ax2 + bx +c=0 are
x = ( -b±(b2 -4ac) ) /2a
putting a=1,b=1 and c=1
we get x = ( -1±3i ) /2 where i = -1
( (-1-3i)/2 )2 = 1/4 ( 1 -3 +23 i) = 1/4 (-2 +23i ) = 1/2 (-1 + 3i )
i.e. square of x1 is equal to x2
Answered by | 21 Sep, 2008, 12:48: PM
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