show that

(x-123)(x-4) +(x-11)(x-14) +(x-2)²=0

Expanding out and collecting the terms of the quadratic equation,

3x² - 156x + 700 = 0

The product of the roots, by comparing with x2+(α+β) + αβ = 0,

is 700/3.

Or

(x-123)(x-4) +(x-11)(x-14) +(x-2)(x-2)=0

Product of the roots = Σproduct of constant terms/total number of products.

= ((-123)(-4)+(-11)(-14)+(-2)(-2))/3 = 700/3

Use this only for qudratic equation.

Regards,

Team,

TopperLearning.