CBSE Class 11-science Answered
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Asked by shekhar14351 | 12 Feb, 2010, 09:30: PM
Expert Answer
(x-123)(x-4) +(x-11)(x-14) +(x-2)2=0
Expanding out and collecting the terms of the quadratic equation,
3x2 - 156x + 700 = 0
The product of the roots, by comparing with x2+(α+β) + αβ = 0,
is 700/3.
Or
(x-123)(x-4) +(x-11)(x-14) +(x-2)(x-2)=0
Product of the roots = Σproduct of constant terms/total number of products.
= ((-123)(-4)+(-11)(-14)+(-2)(-2))/3 = 700/3
Use this only for qudratic equation.
Regards,
Team,
TopperLearning.
Answered by | 13 Feb, 2010, 06:38: AM
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