show that there is no positive integer n for which
Asked by | 17th Jun, 2009, 04:44: PM
Consecutive perfect squares starting from 1 are 1,4,9,16, 25 and so on.
For n-1 to be a perfect square, n=2,5,10,17 ,26 and so on
For n+1 to be a perfect square, n=0,3,8,10,24 and so on
Clearly, both (n-1),(n+1) cannot be rational for any positive integral values of n .So
there is no positive integer n for which (n-1)+(n+1) is rational.
Answered by | 18th Jun, 2009, 05:09: PM
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