show that there is no positive integer n for which
Asked by
| 17th Jun, 2009,
04:44: PM
Consecutive perfect squares starting from 1 are 1,4,9,16, 25 and so on.
For n-1 to be a perfect square, n=2,5,10,17 ,26 and so on
For n+1 to be a perfect square, n=0,3,8,10,24 and so on
Clearly, both (n-1),(
n+1) cannot be rational for any positive integral values of n .So
there is no positive integer n for which (n-1)+(
n+1) is rational.
Answered by
| 18th Jun, 2009,
05:09: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change