show that the square of an positive integer can be of the form 6q+1 or 6q+3 for some integer q.
Asked by FEHMEEDAH NAZNEEN | 30th Aug, 2010, 09:16: PM
The question that you have posted seems to be either wrong or incomplete.
According to your question, we need to prove that there can exist some integer q for which 6q + 1 or 6q + 3 is a square of a positive integer. For that, we need not prove anything. All we need to do is give two examples. Consider q = 0, then 6q+1 = 1 which is a square of 1. and consider q = 1, then 6q+3 = 9 which is the square of 3.
Answered by | 31st Aug, 2010, 02:49: PM
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