show that the diagonals of a parallelogram divide it into four triangles of equal area.

Asked by saima zainab | 26th Feb, 2011, 03:03: PM

Expert Answer:

Dear student,
Here is the solution:
Let ABCD be a parallelogram with diagonals AC and BD intersecting at o. Since the diagonals of a parallelogram bisect each other at point of intersection
therefore, OA=OC and OB=OD
Also, the median of a triangle divides it in two equal parts

Answered by  | 26th Feb, 2011, 12:37: PM

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