SHOW THAT QUADRILATERAL FORMED BY JOINING THE MID POINTS OF ADJACENT SIDES OF A RECTANGLE IS A RHOMBUS
Asked by | 12th Mar, 2013, 12:54: AM
Given :- ABCD is a rectangle and P,Q,R,S are their midpoints.
To Prove:- PQRS is a rhombus.
Proof:- In Tri. ABC, P and Q are the mid points .
So, PQ is parallel AC and PQ = 1/2 *AC (the line segment joining the mid points of 2 sides of the triangle is parallel to the third side and half of the third side)
Similarly RS is parallel AC and RS = 1/2* AC
Hence, both PQ and RS are parallel to AC and equal to 1/2*AC. Hence, PQRS is a parallelogram
In triangles APS & BPQ,
AP=BP (P is the mid point of side AB)
angle PAS = angle PBQ (90 degree each)
and, AS = BQ (S and Q are the mid points of AD and BC respectively and since oppsite sides of a rectangle are equal, so their halves will also be equal)
triangle APS is congruent to triangle BPQ (By SAS)
So, PS=PQ (By CPCT)
PQRS is a parallelogram in which adjacent sides are equal, ...PQRS is a rhombus
Answered by | 12th Mar, 2013, 07:45: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number