Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square.
Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM
Answered by | 4th Jun, 2014, 03:23: PM
- In a parallelogram ABCD the diagonals intersect at O. Prove that AO=CO.
- Diagonals of a parallelogram intersect each other at point O If AO=5,BO=12 and AB=13 then show that quadrilateral ABCD is a rhombus
- if O is a point within a quadrilateral ABCD , show that OA+OB+OC+OD>AC+BD
- Prove that the diagonals of a rhombus are perpendicular to each other.
- PQRS is a square. PR and SQ intersect at O. What is the measure of POQ?
- ABCD is a square prove that diagonal BD bisects B as well as D.
- The lengths of the diagonals of a rhombus are 24 cm and 18 cm respectively. Find the length of each side of the rhombus.
- ABCD is a rhombus ABC = 66o. Determine ACD.
- Prove that the diagonals of a rectangle are of equal length.
- PQRS is a parallelogram and X and Y are points on the diagonal QS such that SX = QY. Prove that PXRY is a parallelogram.
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