Show that any +ve odd integer is of the form 6q+1, or 6q+3, or 6q+5, where q is some integer.
Asked by ankitkhound | 18th Apr, 2010, 08:16: AM
Let a be any odd positive intger and b =6. applying Euclid's Lemma to and b we get
a =6q,6q+1,6q+2,6q+3,6q+4 6q+5 where q is quotient.
Since a is odd so a cannot take values 6q and 6q+2,6q+4.
So a =6q+1,6q+3,6q+5
Answered by | 20th Apr, 2010, 11:07: AM
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