show all the steps.

Asked by akash kumar | 11th Jul, 2017, 04:19: PM

Expert Answer:

begin mathsize 16px style open parentheses straight x to the power of straight b over straight x to the power of straight c close parentheses to the power of straight b squared plus bc plus straight c squared end exponent
equals open parentheses straight x to the power of straight b close parentheses to the power of straight b squared plus bc plus straight c squared end exponent over open parentheses straight x to the power of straight c close parentheses to the power of straight b squared plus bc plus straight c squared end exponent
equals straight x to the power of straight b cross times straight b squared plus straight b cross times bc plus straight b cross times straight c squared end exponent over straight x to the power of straight c cross times straight b squared plus straight c cross times bc plus straight c cross times straight c squared end exponent
equals straight x to the power of straight b cubed plus straight b squared straight c plus bc squared end exponent over straight x to the power of cb squared plus bc squared plus straight c cubed end exponent
equals straight x to the power of open parentheses straight b cubed plus straight b squared straight c plus bc squared close parentheses minus open parentheses cb squared plus bc squared plus straight c cubed close parentheses end exponent
equals straight x to the power of straight b cubed plus straight b squared straight c plus bc squared minus cb squared minus bc squared minus straight c cubed end exponent
equals straight x to the power of straight b cubed minus straight c cubed end exponent
equals straight x to the power of straight b cubed end exponent over straight x to the power of straight c cubed end exponent end style

Answered by Rashmi Khot | 11th Jul, 2017, 04:31: PM