Seven identical disc arranged hexagonal

Asked by aniketchalak145 | 9th Jul, 2021, 07:58: AM

Expert Answer:

Moment of Inertia of central disc , Ic = (1/2) m r2
 
Moment of inertia Ip of each peripheral disc is determined by parallel axis theorem 
 
Ip = (1/2) m r2 + m (2r)2 = (9/2) m r2 
 
Total Moment of Inertia I = Ic + 6 Ip = (1/2) m r2 + 6 [ (9/2) m r2 ]  = (55/2) m r2

Answered by Thiyagarajan K | 9th Jul, 2021, 10:50: AM

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