Sequence and series
Asked by coolameet08 | 14th Feb, 2010, 11:38: AM
S1 = (2n+1)(a + a + (2n+1-1))d)/2
Irrespective of n being even or odd, 2n is always even, so the odd number of terms will be 2n/2 = n,
and if we have total 2n+1 terms the odd terms will be n+1, since the last term will always be odd.
Also series of odd terms is also a AP with common difference 2d.
S2 = (n+1)(a + a + (n+1-1)(2d)/2
S1/S2 = (2n+1)/(n+1)
Answered by | 14th Feb, 2010, 12:00: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number