see below
Asked by | 6th Mar, 2013, 10:47: AM
Expert Answer:
As PB and BQ are tangents from B to the circle so
PB=BQ
Similarly
AP=AR
CR=CQ
AP+PB+CQ=AR+BQ+CR
AB+CQ=AC+BQ
Also
Area of triangle=1/2(AB+BC+AC)*r
=1/2(2s)*r
= ½(perimeter)*r
As PB and BQ are tangents from B to the circle so
PB=BQ
Similarly
AP=AR
CR=CQ
AP+PB+CQ=AR+BQ+CR
AB+CQ=AC+BQ
Also
Area of triangle=1/2(AB+BC+AC)*r
=1/2(2s)*r
= ½(perimeter)*r
Answered by | 6th Mar, 2013, 11:52: AM
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