(secA-tanA)^2.(1+sinA)=1-sinA

Asked by  | 29th Aug, 2012, 09:06: PM

Expert Answer:

LHS
= (secA-tanA)^2.(1+sinA)
= (1-sinA)^2.(1+sinA)/ cos^2A
= (1-sinA)^2.(1+sinA)/ (1-sin^2A)
= (1-sinA)^2.(1+sinA)/ (1-sinA)(1+sinA)
= 1-sinA
= RHS

Answered by  | 29th Aug, 2012, 10:50: PM

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