sec A(1 -sec A)(sec A + tan A)= 1

Asked by ketakiudeshi | 13th Jul, 2019, 02:10: PM

Expert Answer:

The question should be like this
 
sec A(1 - sin A)(sec A + tan A) = 1
 
LHS = sec A(1 - sin A)(sec A + tan A)
       begin mathsize 16px style sec space straight A open parentheses fraction numerator 1 minus sin space straight A over denominator 1 plus sin space straight A end fraction close parentheses cross times open parentheses 1 plus sin space straight A close parentheses open parentheses sec space straight A space plus thin space tan space straight A close parentheses end style
       = begin mathsize 16px style fraction numerator 1 over denominator cos space straight A end fraction cross times fraction numerator 1 minus sin squared space straight A over denominator 1 plus sin space straight A end fraction open parentheses fraction numerator 1 over denominator cos begin display style space end style begin display style straight A end style end fraction plus fraction numerator sin begin display style space end style begin display style straight A end style over denominator cos begin display style space end style begin display style straight A end style end fraction close parentheses end style
       = Error converting from MathML to accessible text.
       = 1
Hence, sec A(1 - sin A)(sec A + tan A) = 1

Answered by Sneha shidid | 15th Jul, 2019, 12:55: PM