Rohan has 10 coins consisting of nickels, dimes, and quarters. Seven of the coins are either dimes or quarters, and eight of the coins are either dimes or nickels. How many dimes does Rohan have?

Asked by Saurabh Budholiya | 2nd Mar, 2011, 03:33: PM

Expert Answer:

Dear Student,
  
Here is the solution:
  
let Dimes = D, Nickels = N and Quarters = Q
  
D+Q = 7............ (i)
D+N = 8............ (ii)
D+Q+N = 10............ (iii)
 
 
Subtituting the value of (i) in (iii)
7+N=10
N=3
 
Putting the value of N in (ii)
D=5
Hence there are 5 dimes.
Regards
Team Topperlearning
 

Answered by  | 2nd Mar, 2011, 09:27: PM

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