is it compulsary to take b=3 in questin number 5 of ncert maths...is so why???...
why can't we take 9 ???as we have to display it in the form of 9m,9m+1 or 9m+8....
Asked by shailesh arlekar | 17th Sep, 2014, 10:06: PM
If b=9, a=9q+r, then we need to give the solutions of all the cases for r=9
Every number which is divisible by 9 is also divisible by 3 and hence 3 is used.
Answered by Vimala Ramamurthy | 18th Sep, 2014, 10:14: AM
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