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Respected Sir , Help me
This Question Calculate C. F. S. C
Asked by dipakmodi2309 | 03 Apr, 2023, 09:51: AM
Expert Answer
Dear Student,
CFSE Fe(CN)6]3−
It is an octahedral complex.
E.C. of Fe3+ = [Ar]3d5
Cynide is s strong field ligand.
Hence, electron distribution of valence electrons would be t2g = 5 electrons, eg = zero electrons.
∆0 = −0.4 x + 0.6 y
Where, x = no. of electrons in t2g
And y = no. of electrons in eg
∆0 = (−0.4 × 5) + (0.6 × 0) = −2.0
(Kindly ask one query at a time)
Answered by | 03 Apr, 2023, 10:24: AM
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