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Respected Sir , Help me This Question Calculate C. F. S. C
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Asked by dipakmodi2309 | 03 Apr, 2023, 09:51: AM
answered-by-expert Expert Answer
Dear Student,
 

CFSE Fe(CN)6]3− 

It is an octahedral complex.

E.C. of Fe3+ = [Ar]3d5

Cynide is s strong field ligand.

Hence, electron distribution of valence electrons would be t2g = 5 electrons, eg = zero electrons.

∆0 = −0.4 x + 0.6 y

Where, x = no. of electrons in t2g

And y = no. of electrons in eg   

∆0 = (−0.4 × 5) + (0.6 × 0) = −2.0

(Kindly ask one query at a time)

Answered by | 03 Apr, 2023, 10:24: AM

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