resistors in series and parallel.
Asked by deepitapai | 5th Feb, 2009, 04:15: PM
If three resistance of 2 Ω are connected in series in one branch, then the resistance of each branch = 2+2+2 = 6Ω.
4 similar sets are connected in parallel. Hence the net resistance R' is given as
1/R' = 1/6 + 1/6 + 1/6 + 1/6 = 4/6
R' = 6/4 = 3/2 = 1.5Ω
Answered by | 5th Feb, 2009, 06:19: PM
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