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(Costheta-Sintheta)(1+tantheta) =Sectheta
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2Cos^2theta-1
 

Asked by tejvarun | 15th Jun, 2017, 05:38: PM

Expert Answer:

begin mathsize 16px style open parentheses cosθ minus sinθ close parentheses open parentheses 1 plus tanθ close parentheses
equals open parentheses cosθ minus sinθ close parentheses open parentheses 1 plus sinθ over cosθ close parentheses
equals open parentheses cosθ minus sinθ close parentheses cross times fraction numerator cosθ plus sinθ over denominator cosθ end fraction
equals fraction numerator cos squared straight theta minus sin squared straight theta over denominator cosθ end fraction
equals fraction numerator cos squared straight theta minus open parentheses 1 minus cos squared straight theta close parentheses over denominator cosθ end fraction
equals open parentheses 2 cos squared straight theta minus 1 close parentheses cross times 1 over cosθ
equals secθ open parentheses 2 cos squared straight theta minus 1 close parentheses end style

Answered by Sneha shidid | 15th Jun, 2017, 06:05: PM