Repulsion in OH2 is greater than SH2 ,why?

Asked by Sneha Kashyap | 17th Nov, 2013, 07:31: PM

Expert Answer:

Electronegativity of O-atom is greater than that of S-atom, so the bonding electron pair used in the formation of O-H bond is shifted more towards more electronegative O-atom than the bonding electron pair of S-H bond is shifted towards less electronegative S-atom.

Thus the electron density on O-atom is more than that on S-atom. As a result the (bp-bp) repulsion in H2O molecule becomes greater than the (bp-bp) repulsion in H2S molecule.

Answered by Vaibhav Chavan | 18th Nov, 2013, 12:00: PM

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