represent 1+2i/1-3iin the polar form

Asked by monami chatterjee | 26th Aug, 2010, 06:56: PM

Expert Answer:

z=1+2i1-3i= 1+2i1-3ix1+3i1+3i = -5+5i10= -1+i2If z = x+iy then Z= x2+y2   and tanθ=yx z=-122+122=12  and  tanθ=1/2-1/2=-1If tanθ =1 then  θ= 4As the point -1/2, 1/2 is in second quadrant, θ = -4= 34Polar form of z is 12cos34 +i sin34">

Answered by  | 26th Aug, 2010, 08:35: PM

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