Asked by pkartik | 1st Feb, 2009, 08:17: AM
Note that when a triangle is cut by a line parallel to the base , then the smaller triangle and the bigger triangle are similar( use AA similarity for this)
suppose ABC is cut by a line DE parallel to BC.
So, triangle ABC and triangle ADE are the similar triangles.
We know that the ratio of areas of similar triangles is equal to the ratio of the square of their corresponding sides.
According to question,
area (ADE) is the same as area (BCED)
So, this tells us that
area (ABC)=are(ADE)+area(BCED)=2 area(ADE).
SO, are( ABC)=2 area (ADE)
Answered by | 1st Feb, 2009, 09:15: AM
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