refraction of light by a glass slab. explain.

 

Asked by anchaltamrakar090 | 25th Nov, 2019, 12:21: PM

Expert Answer:

Consider a rectangular glass slab ABCD having parallel faces AB and CD as shown in above figure. A ray of light EF in air is incident on the glass surface AB at point O. As the ray EO enters from air (rarer medium) to glass (denser medium), the ray bends towards normal and follows the path OO' inside the glass slab. At point O', refraction takes place again. As the ray OO' enters from glass (denser medium) to air (rarer medium), the ray bends away from normal and follow the path O'H outside glass slab.

Here, the ray EF is called incident ray, OO', the refracted ray and O'H, the emergent ray.

As per the laws of refraction,  and.

The emergent ray O'H is parallel to the incident ray EF. The perpendicular distance O'L between the original path of incident ray and the emergent ray is called the lateral displacement.

Answered by Shiwani Sawant | 25th Nov, 2019, 12:59: PM