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CBSE Class 11-science Answered

Redox Reaction: solve the following equation by ion electron method in acidic medium  
question image
Asked by kkdmmdsd | 09 Jun, 2019, 04:27: PM
answered-by-expert Expert Answer
In ion electron method, divide the equation in two part 
 
Mn to the power of plus 2 space end exponent plus space ClO subscript 3 to the power of minus rightwards arrow space MnO subscript 2 plus Cl to the power of minus plus 2 space space space space space space space space plus 5 space space space space space space space space space space space plus 4 space space space space space minus 1 Oxidation minus Mn to the power of plus 2 end exponent rightwards arrow MnO subscript 2 left parenthesis 1 right parenthesis space Add space straight H subscript 2 straight O space to space balance space straight O space atoms Mn to the power of plus 2 end exponent plus 2 straight H subscript 2 straight O rightwards arrow MnO subscript 2 left parenthesis 2 right parenthesis space Add space straight H to the power of plus space space end exponent ions space to space balance space straight H space atoms Mn to the power of plus 2 end exponent plus 2 straight H subscript 2 straight O rightwards arrow MnO subscript 2 plus 4 straight H to the power of plus left parenthesis 3 right parenthesis Add space electrons space to space balance space charge space on space both space side Mn to the power of plus 2 end exponent plus 2 straight H subscript 2 straight O rightwards arrow MnO subscript 2 plus 4 straight H to the power of plus plus 2 straight e to the power of minus space space space space space space space space space space space space space space space space............... left parenthesis 1 right parenthesis Reuduction minus ClO subscript 3 to the power of minus rightwards arrow Cl to the power of minus left parenthesis 1 right parenthesis space Add space straight H subscript 2 straight O space to space balance space straight O space atoms ClO subscript 3 to the power of minus rightwards arrow Cl to the power of minus plus 3 straight H subscript 2 straight O left parenthesis 2 right parenthesis Add space straight H to the power of plus space space end exponent ions space to space balance space straight H space atoms ClO subscript 3 to the power of minus plus 6 straight H to the power of plus rightwards arrow Cl to the power of minus plus 3 straight H subscript 2 straight O left parenthesis 3 right parenthesis space Add space electrons space to space balane space charge space on space both space side ClO subscript 3 to the power of minus plus 6 straight H to the power of plus plus 7 straight e to the power of minus rightwards arrow Cl to the power of minus plus 3 straight H subscript 2 straight O space space space space space space space space space space space space space space................... left parenthesis 2 right parenthesis After space adding space equation space left parenthesis 1 right parenthesis space and space left parenthesis 2 right parenthesis We space will space get comma 2 ClO subscript 3 to the power of minus plus 7 Mn to the power of plus 2 end exponent plus 8 straight H subscript 2 straight O rightwards arrow 7 MnO subscript 2 space plus space 2 Cl to the power of minus plus space 16 straight H to the power of plus
Answered by Ravi | 10 Jun, 2019, 12:43: PM

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