Asked by monicasyal | 17th May, 2010, 10:19: PM
suppose n is divisible by 3
n is a multiple of 3, then the next multiple of 3 will be n+3, then after that n+6... and so on..
so if n is a multiple of 3 then n+2 and n+4 can't be multiples of 3, so we have proved the required.
if n+2 is a multiple of 3, then the multiple before that would be n-1, and the one after n+2 would be n+5
so if n+2 is a multiple of 3 then neither n nor n+4 can be a multiple of 3, so we have proved it again.
you can prove the third part similarly.
Answered by | 18th May, 2010, 02:19: PM
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