radius of earth

Asked by princy ojha | 27th Sep, 2010, 01:47: PM

Expert Answer:

Dear Student,

Since the earth flattens in the poles the distance to the center of the earth is larger in the equator and therefore its gravity is stronger there.
Also, the downward force of gravity is opposed by an outward centrifugal force due to the planet's rotation, which is greater at the equator than at a higher latitudes.
Overall these two effects result in a variation of 0.052 m/s2 (0.171 ft/s2) in the value of g, which leads to a variation in the weight of an object by about 0.5% depending on whether it is weighed at the equator or at one of the poles. Taking an average over the whole surface of the Earth, physicists have arrived at a standard value for g of 9.80665 m/s2 (32.1740 ft/s2). 
We hope that clarifies your query.

Answered by  | 27th Sep, 2010, 06:15: PM

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