questions

Asked by sweetynam | 30th May, 2008, 01:31: PM

Expert Answer:

Yes....but only when the object is virtual.....in the mirror formula put the object distance as +ve , 1/f is 0

then v = -ve therefore the image is real.

regards

toppers expert

Answered by  | 3rd Jun, 2008, 11:16: PM

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